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DUAL OF THE AUSLANDER-BRIDGER FORMULA AND GF-PERFECTNESS

PARVIZ SAHANDI and TIRDAD SHARIF

Abstract

Ext-finite modules were introduced and studied by Enochs and Jenda. We prove under some conditions that the depth of a local ring is equal to the sum of the Gorenstein injective dimension and Tor-depth of an Ext-finite module of finite Gorenstein injective dimension. Let(R,)be a local ring. We say that anR-moduleMwith dimRM=nis aGrothendieck moduleif then-th local cohomology module ofMwith respect to, Hn(M), is non-zero. We prove the Bass formula for this kind of modules of finite Gorenstein injective dimension and of maximal Krull dimension.

These results are dual versions of the Auslander-Bridger formula for the Gorenstein dimension.

We also introduce GF-perfect modules as an extension of quasi-perfect modules introduced by Foxby.

1. Introduction

Throughout this paper all rings are commutative and Noetherian with nonzero identity. In [8] and [10] Enochs and Jenda introduced and studied mock finite Gorenstein injective modules. As an extension they introduced and studied the Ext-finite modules of finite Gorenstein injective dimension in [11]. We recall that an R-module M is called Ext-finit if ExtiR(N, M) is finite (i.e.

finitely generated) for each finiteR-moduleN and fori ≥1. Therefore, every finiteR-moduleM is Ext-finite and it is also easy to see that every cosyzygy of an Ext-finite module is also Ext-finite [11, (4.7)]. In section 2, following Enochs and Jenda in [11] we prove a dual result for the Auslander-Bridger formula [1] for Ext-finite modules of finite Gorenstein injective dimension.

Our approach to obtain a dual result is fundamentally different from the method of Enochs and Jenda in [11]. In this direction, we show that anR-moduleM with finite Gorenstein injective dimension (Gid) has a surjective precoverN, such that GidRM = idRN, with respect to the classI0 of modules of finite injective dimension. We call theR-moduleN anI0-precover ofM. Viewing this, we introduceGI-syzygymodules for modules of finite Gorenstein injective dimension, see (2.3). These objects play an important role to prove one of our main results in Section 2, see Theorem (2.4).

The second author is supported by a grant from IPM (No. 83130311) Received January 19, 2006.

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Let(R,)be a local ring, and letM be anR-module of Krull dimension n. We say that M is aGrothendieck module, if the n-th local cohomology module ofMwith respect toᒊ, Hn(M), is non-zero. From the non-vanishing Theorem of Grothendieck [4, (6.1.4)] it follows that all finite modules are Grothendieck modules. In [20] R. Sazeedeh used local cohomology to study the Gorenstein injective modules over Gorenstein rings. By developing his method over arbitrary local rings, we prove a dual result for the Auslander- Bridger formula, see Theorem (2.7).

In Section 3 we introduce and study a new invariant for anR-moduleM denoted by F-gradeRMwhich is, an extension of the usual notion of gradeRM introduced by Rees in [18]. AnR-moduleMof finite Gorenstein flat dimension (Gfd) is called GF-perfect if F-gradeRM =GfdRM. This concept generalizes the notion ofquasi-perfectnessintroduced by Foxby in [13]. We prove that for GF-perfect modules of finite depth over Cohen-Macaulay local rings we have dimRM = depthRM. In Corollary (3.9) we state an Auslander-Bridger for- mula for GF-perfect modules of finite depth over Cohen-Macaulay rings. We also investigate the behavior of GF-perfect modules under the first fundamental change of rings, see Corollary (3.12).

Throughout this paper, we use the following notions:

(1) The Gorenstein injective modules were introduced by Enochs and Jenda in [8]. AnR-moduleM is said to be Gorenstein injective if and only if there is an exact sequence

· · · −→E1−→E0−→E1−→ · · ·

of injectiveR-modules such thatM = ker(E0 −→ E1), and such that for any injectiveR-moduleE, HomR(E,)leaves the complex above exact. The above complex is known as complete injective resolution.

(2) The Gorenstein flat modules were introduced by Enochs, Jenda, and Torrecillas in [9]. AnR-moduleM is said to be Gorenstein flat if and only if there is an exact sequence

· · · −→F1−→F0−→F1−→ · · ·

of flat R-modules such that M = ker(F0 −→ F1), and such that for any injective R-module I, IR− leaves the complex above exact. The above complex is known as complete flat resolution.

(3) The Gorenstein flat dimension (Gfd) and the Gorenstein injective di- mension (Gid), respectively are defined by using the Gorenstein flat modules and the Gorenstein injective modules, by a similar fashion as the flat dimension (fd) and the injective dimension (id), respectively are defined.

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(4) LetX be a class ofR-modules for some ringR. Ifφ : X −→ M is linear whereXX andM is anR-module, thenφ : X−→ M is called an X-precover ofM if

HomR(Y, X)−→HomR(Y, M)−→0 is exact for allYX.

(5)P0= {M |M is an R-module of finite projective dimension}. (6)I0= {M |M is an R-module of finite injective dimension}. 2. Dual of the Auslander-Bridger formula

In this section we prove a dual of the Auslander-Bridger formula in Theor- ems (2.4) and (2.7). In order to prove the theorems we need two lemmas. The following lemma gives a characterization for Cohen-Macaulay local rings.

Lemma2.1.Let (R,,k) be a local ring and letNbe anExt-finiteR-module of finite injective dimension and of finitedepth. Then

idRN =sup{i|ExtiR(T , N )=0for someTP0withR(T ) <∞}, if and only ifRis a Cohen-Macaulay ring.

Proof. First of all suppose that the equality holds. Then there is an R- moduleT of finite length and of finite projective dimension. HenceRis Cohen- Macaulay by the Intersection Theorem cf. [19]. Conversely, suppose thatRis a Cohen-Macaulay ring. By [21, (1.4)]n=idRN =sup{i |ExtiR(k, N )=0}. Then ExtnR(k, N )=0. Letx1, . . . , xt be a maximalR-sequence inᒊ. Since Ris Cohen-Macaulayᒊ∈Ass(R/(x1, . . . , xt)). LetT =R/(x1, . . . , xt). So we have the exact sequence 0−→k−→T −→L−→0, which induces the exact sequence

ExtnR(T , N )−→ExtnR(k, N )−→0.

So that ExtnR(T , N )=0, and this completes the proof.

Lemma2.2. LetRbe a ring and letMbe anR-module withGidRM <. Then there is a surjective I0-precover ϕ : N −→ M such that idRN = GidRM andkerϕis a Gorenstein injectiveR-module.

Proof. We use an induction argument ong =GidRM. Ifg =0, thenM is Gorenstein injective. So by definition of the Gorenstein injective modules, there is the exact sequence

0−→H −→I −→M −→0,

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in whichIis injective andH is Gorenstein injective. By [8, Proposition (2.4)]

it is clear thatIis anI0-precover ofM. Now letg 1. From [16, (2.15)] there is a Gorenstein injective moduleGand anR-moduleLwith idRL = g−1 such that the following sequence is exact

0−→M −→G−→L−→0.

SinceGis Gorenstein injective we have the following pullback diagram

0 0

↓ ↓

H H

↓ ↓

0−−−−→N −−−−→ E−−−−→L−−−−→0

↓ ↓

0−−−−→M −−−−→G−−−−→L−−−−→0

↓ ↓

0 0

whereH is Gorenstein injective module and idRN = g. Now from [8, Pro- position (2.4)] it follows that in the exact sequence

0−→H −→N −→M −→0, Nis anI0-precover ofM such that idRN =GidRM.

LetMbe anR-module with GidRM <∞. From the above lemma we have the exact sequence

0−→H1−→N −→M −→0,

whereH1is Gorenstein injective. From the definition of Gorenstein injective modules there is an injectiveR-moduleE1and a Gorenstein injective module H2such that the following sequence is exact.

0−→H2−→E1−→H1−→0.

By continuing in the same manner we can find Gorenstein injective modules Hi and injective modulesEi fori1 such that the sequence

· · · −→E2−→E1−→N −→M −→0,

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is exact. It is clear that idRM <∞if and only if the above sequence is finite.

Definition2.3. In the above construction we call theR-modulesHi for i1 thei-thGI-syzygy module ofM.

Now we are in the position of proving the first main result of this section.

Recall that

Tor-depthRM =inf{i|TorRi (k, M)=0}.

It is shown in [15, (14.17)] that Tor-depthRMis finite if and only if depthRM is finite.

Theorem2.4. Let(R,, k)be a Cohen-Macaulay local ring and letMbe anExt-finiteR-module of infinite injective dimension. If GidRM <and M has anExt-finite GI-syzygy module, then

GidRM+Tor-depthRM =depthR.

Proof. Letg = GidRM. Ifg =0, then [11, (4.1)] gives the result. Now suppose thatg 1, soM has anI0-precoverN, with idRN = g, and such that in the exact sequence

() 0−→H −→N −→M −→0

H is a Gorenstein injective module with idRH = ∞. By definition of GI- syzygy modules ofM, it is easy to see thatH is an Ext-finite module. So by [11, (4.1)] Tor-depthRH = depthR = dimR = d. If Tor-depthRM = ∞, from the long exact sequence of homologies we get that Tor-depthRN = Tor-depthRH = d. Since M and H are Ext-finite modules, then so isN. Now from [21, (1.6)] it follows that idRN = 0. This yields that g = 0, which is a contradiction, hence Tor-depthRM <∞. On the other hand, since Tor-depthRH = d, we get depthRH = 0 by [15, (14.18)], and this yields that depthRN = 0. So we obtain that Tor-depthRN < ∞by [15, (14.18)]

again. Since R is a Cohen-Macaulay ring, from Lemma (2.1) we get that ExtgR(T , N ) = 0 for someTP0(R)of finite length. From the long exact sequence induced by ()and [8, Proposition (2.4)] we find that there is an exact sequence as follows

0=ExtgR(T , H )−→ExtgR(T , N )−→ExtgR(T , M)−→0.

Therefore

GidRM =sup{i|ExtiR(T , M)=0 for someTP0withR(T ) <∞},

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and so we find that GidRM

=sup{i |HomR(ExtiR(T , M), E(k))=0 for someTP0withR(T ) <∞}

=sup{i |TorRi (T ,Hom(M, E(k)))=0 for someTP0withR(T ) <∞}. On the other hand, since depthRT = 0 and depthRHomR(M, E(k)) = Tor-depthRM, from [22, (2.3)], it follows that the right side of the second equality is depthR−Tor-depthRM as desired.

Now it is natural to ask the following question:

Question2.5. How can we decide about the Ext-finiteness (mock finite- ness) ofN in Lemma 2.2, whenM is an Ext-finite (mock finite) module?

Note that a consequence of an affirmative answer to our question gives a dual result for the Auslander-Bridger formula as follows:

Let(R,, k)be a Cohen-Macaulay local ring and letM be a mock finite R-module with GidRM <∞and of infinite injective dimension. Then

GidRM +Tor-depthRM =depthR.

In the rest of this section we introduce a class of modules calledGrothen- dieck modules. We find a dual result for the Auslander-Bridger formula for this kind of modules of maximal dimension.

Definition 2.6. AnR-moduleM of Krull dimension n, is said to be a Grothendieck moduleif Hn(M)=0.

The following result is analogous to a classical result due to H. Bass [3].

In [23] Takahashi proved the following theorem for finite modules, under the additional assumption that the base ring admits a dualizing complex. In [25]

Yassemi, proved Takahashi’s result, without assuming that the ring admits a dualizing complex.

Theorem2.7. Let (R,)be a local ring and letM be a Grothendieck module withGidRM <. IfdimM =dimR, thenRis a Cohen-Macaulay ring andGidRM =depthR.

Proof. Letg=GidRMand letn=dimM. By a similar argument to that of [20, (3.1)] it is easy to see that Hi(H )= 0 when GidRH = 0 andi >0.

Now from Lemma (2.2) it is clear that for i > 0, Hi(M) = Hi(N )when N is anI0-precover ofM such that idRN = g. It is easy to see that in this case Hi(N )=0 fori > g. On the other hand, since dimN =dimM,Nis a

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Grothendieck module too. Thereforen≤idRN. Now we have the following (in)equalities:

n=dimR≤idRN =depthR−Tor-depthRN≤htᒍ

in which the second equality holds by [6, (3.1)], so we obtainᒍ = ᒊ. This ends our proof.

Recall from [5] that anR-moduleMis said to be have rankr, ifMis a free R-module of rankr, for all prime idealsᒍ ∈ Ass(R). It is clear that, finite modules with positive rank are of maximal Krull dimension.

Corollary2.8. IfMis a finite module of positive rank with finite Goren- stein injective dimension, thenRis a Cohen-Macaulay ring.

It is interesting to know that there is a large class of non-finite modules satisfying both conditions of Theorems 2.4 and 2.7.

Example2.9. Let (R,, k)be an n-Gorenstein local ring which is not regular, and letLbe anR-module withR(L) <∞and idRL= ∞. LetE· be the minimal injective resolution ofL. Therefore, each term ofE·, is direct sum of finitely many copies ofE(k), the injective envelope ofk. So all terms ofE· areᒊ-torsion, in the sense of [4]. LetH be ther-th cosyzygy of this resolution forr n. By [11, (4.2) and (4.7)]H is Gorenstein injective and Ext-finite. So, by [8, (6.5)]H is a mock finite module. Viewing [8, (6.6)] we get that, the firstGI-syzygy ofHis mock finite too. SetM =HR, now it is clear thatM is an Ext-finite, GrothendieckR-module with dimM =dimR.

3. GF-Perfect modules

LetM be a finiteR-module, the notion gradeRM was defined by Rees as the least integer 0 such that ExtR(M, R) = 0. In [18] Rees proved that the gradeRM is the maximum lengths ofR-regular elements in AnnR(M). It is easy to see that gradeRMis the least integer0 such that ExtR(M, P )=0 for some projectiveR-module P. When M is a non-finite R-module there is not any extension of this important invariant, however in any extension of grade, a homological view is useful. In this section for an arbitraryR-module Mwe introduce a new invariant denoted by F-gradeRM, such that whenMis finite then F-gradeRM =gradeRM. One important concept closely related to the grade of modules isperfectness. A finiteR-moduleM with pdRM < ∞ is said to beperfectif gradeRM = pdRM. This concept was generalized by Foxby in [13] where he definedquasi-perfectmodules. A finiteR-moduleM with G-dimRM <∞is said to bequasi-perfectif gradeRM =G-dimRM(in which G-dimRMis Gorenstein dimension ofMintroduced by Auslander and

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Bridger in [1]). The perfect and quasi-perfect modules over Cohen-Macaulay local rings are Cohen-Macaulay modules, see [5] and [13], respectively. In this section a generalization of this fact over Cohen-Macaulay local rings is proved in Theorem (3.7) below.

Definition3.1. LetM be anR-module. TheFlat gradeofM is denoted by F-gradeRM, and it is defined by the following formula

F-gradeRM =inf{i|ExtiR(M, F )=0 for some flatR-moduleF}. By definition it is clear that F-gradeRM gradeRM.

Remark3.2. LetMbe a finiteR-module and suppose that F-gradeRM = . Then there is a flat R-module F such that ExtR(M, F ) = 0. SinceM is finite, ExtR(M, F )ExtR(M, R)RF and so ExtR(M, R)=0. Therefore, gradeRM .Now we have F-gradeRM =gradeRM.

It is not difficult to see that F-gradeRM GfdRM, it is also a trivial con- sequence of the following proposition. Recall from [24, Definition (3.1.1)] that anR-moduleCis called cotorsion, if for all flatR-modulesF, Ext1R(F, C)= 0. The following proposition shows that F-grade and Gfd can be computed via cotorsion flat modules.

Proposition3.3. LetRbe a ring and letMbe anR-module. Then F-gradeRM= inf{i|ExtiR(M, F )=0 for some cotorsion flatR-moduleF}, and ifGfdRM <, then

GfdRM =sup{i |ExtiR(M, F )=0 for some cotorsion flatR-moduleF}. Proof. If F-gradeRM = ∞, then ExtiR(M, F )=0 for all flatR-modules, thus the right side is infinity too. Let F-gradeRM =n, therefore ExtnR(M, F )

=0 for some flatR-moduleF. Now letQbe the pure injective envelope ofF cf. [24]. By [24, (3.1.6)]Q/F =H is flat, thus ExtiR(M, H )= 0 fori < n.

On the other hand the exact sequence 0 −→F −→ Q−→ H −→0 gives rise to an injection

0−→ExtnR(M, F )−→ExtnR(M, Q)−→ · · ·.

Therefore ExtnR(M, Q) = 0. Keep in mind that pure injective modules are cotorsion.

Now letg = GfdRM < ∞. From [16] we can find an injective module J such that TorRg(M, J ) = 0. Therefore HomR(TorRg(M, J ), Q) = 0 for a

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faithfully injectiveR-moduleQ. This yields that ExtgR(M,HomR(J, Q))=0.

By settingF = HomR(J, Q)and considering the simple fact thatF is a flat cotorsionR-module, we see that the right side is greater than or equal tog.

On the other hand, letF be a cotorsion flatR-module. Therefore, from [12, (2.3)] it follows that there is a flatR-moduleH, and injectiveR-modulesJ1 andJ2such thatFH =HomR(J1, J2). Let for somei > g, ExtiR(M, F )= 0. Hence ExtiR(M,HomR(J1, J2)) = HomR(TorRi (M, J1), J2) = 0 and so TorRi (M, J1) = 0. From this and [16] we have GfdRM > g, which is a contradiction.

Definition3.4. LetM be anR-module with GfdRM <∞. We callM Gorenstein flat perfect (GF-perfect for short) if F-gradeRM =GfdRM.

Note that a finite R-module M is quasi-perfect if and only if it is GF- perfect, because G-dimRM = GfdRM by [9] and F-gradeRM = gradeRM by Remark 3.2.

Lemma3.5. LetRbe a ring and letM be aGF-perfectR-module, then for ᒍ∈SuppRM,Mis aGF-perfectR-module.

Proof. Since GfdRM < ∞it is easy to see that GfdRM < ∞. Thus we have F-gradeRM GfdRM < ∞. Set F-gradeRM = n. So there is a flatR-moduleQsuch that ExtnR(M, Q)=0. Consider anR-projective resolutionP. −→ M, henceP. is a projective resolution for M. Now we have the following equalities

0=ExtnR(M, Q)=Hn(HomR(P., Q))

=Hn(HomR(P., Q))=ExtnR(M, Q)

SinceQis also flat as anR-module, then F-gradeRM n. Hence we have the following chain of inequalities

F-gradeRM F-gradeRMGfdRMGfdRM.

Since M is GF-perfect so GfdRM = F-gradeRM, thereforeMp is also GF- perfectR-module.

The following lemma is well known [14]. We include a proof here for completeness.

Lemma3.6.Let(R,)be a local ring withcmdR=dimR−depthR1.

If,∈Spec(R)and⊆ᒎ, thendepthRdepthR.

Proof. If cmdR = 0 there is nothing to prove. Now we can assume cmdR =1. We will induct ond =dimR. Ifd =0 it is trivial. Assumed >0,

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and let ⊆ ᒎ. If = ᒊ, viewing [2], we get that depthR dimR−1 = depthR. Now letᒎ= ᒊ, since dimR d and cmdR cmdR 1, by the induction hypothesis we have depthR=depth(R)R depthR.

In the following theorem we generalized, results of Rees and Foxby in [18]

and [13]. For the proof we need to recall the definition of the invariant Rfd which is called Large Restricted flat dimension, introduced and studied by Christensen, Foxby and Frankild in [7]. It is defined by the formula

RfdRM =sup{i|TorRi (L, M)=0 for someR-moduleLwith fdRL <∞}. This number is finite, as long asMis nonzero and the Krull dimension of R is finite; see [7, (2.2)]. They proved that, see [7, (2.4)]

RfdRM =sup{depthR−depthRM|ᒍ∈Spec(R)}.

Theorem3.7. Let(R,)be a local ring such thatcmdR 1. Then for anyGF-perfectR-moduleMof finitedepthwe have:

depthR−depthRM F-gradeRM dimR−dimM.

In particular, ifRis a Cohen-Macaulay ring, thendepthRM =dimM. Proof. First of all we show that for eachᒍ ∈ AssR(M), F-gradeRM = depthR.Chooseᒍ∈AssR(M). Thus depthRM= 0. Since GfdRM <∞ therefore by [7] and [16, (3.19)] we have

depthR=depthR−depthRMGfdRM.

Since GfdRM<∞, there is by [16, (3.19)] a prime ideal⊆ᒍsuch that GfdRM=depthR−depthRM.

Hence by noting Lemma (3.6) we have:

GfdRMdepthR−depthRMGfdRM−depthRM. By Lemma (3.5)M is GF-perfect asR-module and GfdM = GfdRM. Hence depthRM=0 and

depthRGfdRM =GfdRMdepthR. Now our first claim is proved.

Chooseᒍ ∈ AssR(M)such that dimRM = dimR/. The following in- equalities are clear

() dimRM+gradeR()dimR/+htᒍdimR.

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Since cmdR1, using [5, (1.2.10)] we have:

gradeR()=inf{depthR|ᒍ⊆ᒎ} =depthR.

By our first claim sinceᒍ∈AssR(M), F-gradeRM =depthR=gradeR().

By()we have

dimRM+F-gradeRM dimR,

which is the second equality. Since F-gradeRM = GfdRM, by [7] and [16, (3.19)], we get that depthR−depthRM F-gradeRM.This completes the proof.

The following Example shows that the hypothesis of finiteness of depth is necessary.

Example3.8. Let(R,)be a local domain with dimR > 0 and letK be its fraction field. It is clear thatKis GF-perfect but depthRK = ∞and dimRK=dimR.

The following result is analogous to the Auslander-Bridger formula for the Gorenstein dimension [1]. We remark that, whenRis a Cohen-Macaulay local ring andMis a finiteR-module, it is clear that, gradeRM+dimRM =dimR.

Viewing this, the following result is also an extension of this fact in the non- finite case.

Corollary3.9. Let(R,)be a local Cohen-Macaulay ring and letM be aGF-perfect module of finitedepth. Then

GfdRM +depthRM =depthR.

Lemma3.10. LetR be a ring and letxbe anRandM-regular element.

SetS=R/xR. Then

RfdRM =RfdS(M/xM).

Proof. SetX¯ =XRSfor a moduleX. It is a simple computation that in the exact sequence

0−→K−→F −→M −→0,

whenF is a flat R-module we have RfdRK = 0, if RfdRM = 0 and if RfdRM > 0 then RfdRK = RfdRM −1. We will induct onn = RfdRM. LetLbe a module such that fdSL <∞, thus fdRL <∞. By [17, page 140], we have TorSi(L, M) = TorRi (L, M). So if RfdRM = 0 thus RfdSM = 0.

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Now letn >0. Consider the exact sequence 0−→K −→F −→M −→0, whereF is a free module. Sincexis bothF andM-regular, by [5, (1.1.5)] the following sequence is again exact

0−→K−→F −→M −→0.

By the induction hypothesis RfdSK=n−1 and so RfdSM =n.

The following theorem is a generalization of a theorem due to Auslander and Bridger in [1] on the behavior of the Gorenstein dimension under base change.

Theorem3.11. LetRbe a ring and letMbe anR-module withGfdRM <

. Letxbe anRandM-regular element, and letS=R/xR. Then (1) GfdRM =GfdS(M/xM).

(2) GfdR(M/xM)=GfdRM +1.

Proof. SetX¯ =XRSfor a moduleX. For part (1) we argue by induction ong = GfdRM. Letg = 0, soM is a Gorenstein flatR-module. Consider a complete resolution of flat modules as the following

· · · −→F1−→1 F0−→0 F1−→−1 F2−→ · · ·

such thatM ker0; and for alli ∈Zeach keri = Mi is a Gorenstein flat R-module and has the flat resolution as

· · · −→Fi+2−→Fi+1−→Mi −→0.

Sincex is Mi-regular andFi-regular for alli, by [5, (1.1.5)] the following sequence is again exact

· · · −→Fi+2−→Fi+1−→Mi −→0.

If we splice these sequences to each other we get a long exact sequence of flat S-modules

() · · · −→F1−→1 F0−→0 F1−→−1 F2−→ · · ·. LetJ be an injectiveS-module, hence by [17, page 140] we have

TorS(J, Mi)=TorR(J, Mi) for all 0.

Since idRJ < ∞, TorR(J, Mi) = 0 for > 0. So () is a complete flat resolution ofS-modules such thatM = ker0 and henceM is a Gorenstein flatS-module.

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Now letg >0, so there is a Gorenstein flatR-moduleGand anR-module Lwith GfdRL=g−1, such that the following sequence is exact

0−→L−→G−→M −→0.

SincexisG-regular, by [5, (1.1.5)] the following sequence ofS-modules is exact

0−→L−→G−→M −→0.

By the induction hypothesis, GfdSL= g−1 and GfdSG = 0, therefore GfdSM <∞. Now [16, (3.19)] and lemma (3.10) give the desired equality.

(2) SincexisM-regular we have

0−→M −→.x M −→M −→0.

From [16] we have GfdRM <∞, and by [16, (3.19)] and [22, (3.6)] we get GfdRM = RfdRM = RfdSM + 1. But from Lemma (3.10) we find that GfdSM =RfdSM =GfdRM and this completes the proof of part (2).

Corollary3.12. LetRbe a ring and letMbe aGF-perfectR-module. If xis anRandM-regular element andS= R/xRandM = M/xM, thenM is aGF-perfectS-module.

Proof. It follows from Theorem (3.11) that GfdSM < ∞, and so F-gradeSM < ∞. Let n = GfdRM = F-gradeRM andm = F-gradeSM. Thus there is a flatS-moduleF, such that ExtmS(M, F )=0. Since fdRF <∞, using [17, page 140] it is not difficult to see thatnm. On the other hand, by Theorem (3.11),n=GfdRM =GfdSM ≥F-gradeSM =m, and son=m.

Now it follows thatM is a GF-perfectS-module.

Acknowledgement.We are grateful to the referee for carefully reading the first version of this article. Parviz Sahandi would like to thanks his supervisor Professor Siamak Yassemi for using his grant from (IPM) (No. 84130216).

REFERENCES

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DEPARTMENT OF MATHEMATICS UNIVERSITY OF TEHRAN TEHRAN

IRAN

E-mail:sahandi@ipm.ir

INSTITUTE FOR STUDIES IN THEORETICAL PHYSICS AND MATHEMATICS

TEHRAN IRAN

E-mail:sahandi@ipm.ir, sharif@ipm.ir

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