SEQUENCES FOR COMPLEXES II
LARS WINTHER CHRISTENSEN
1. Introduction and Notation
This short paper elaborates on an example given in [4] to illustrate an applic- ation of sequences for complexes:
LetRbe a local ring with a dualizing complexD, and letMbe a finitely generatedR-module; then a sequencex1, . . . , xn is part of a system of parameters forMif and only if it is aRHomR(M, D)-sequence [4, 5.10].
The final Theorem 3.9 of this paper generalizes the result above in two directions: the dualizing complex is replaced by a Cohen-Macaulay semi- dualizing complex (see [3, Sec. 2] or 3.8 below for definitions), and the finite module is replaced by a complex with finite homology.
Before we can even state, let alone prove, this generalization of [4, 5.10]
we have to introduce and study parameters for complexes. For a finite R- moduleM everyM-sequence is part of a system of parameters for M, so, loosely speaking, regular elements are just special parameters. For a complex X, however, parameters and regular elements are two different things, and kinship between them implies strong relations between two measures of the size ofX: theamplitudeand theCohen-Macaulay defect(both defined below).
This is described in 3.5, 3.6, and 3.7.
The definition of parameters for complexes is based on a notion ofanchor prime ideals. These do for complexes what minimal prime ideals do for mod- ules, and the quantitative relations between dimension and depth under dagger duality—studied in [3]—have a qualitative description in terms of anchor and associated prime ideals.
ThroughoutRdenotes a commutative, Noetherian local ring with maximal idealᒊand residue fieldk=R/ᒊ. We use the same notation as in [4], but for convenience we recall a few basic facts.
The homological position and size of a complexXis captured by thesu-
Received May 2, 2000.
premum,infimum, andamplitude:
supX =sup{∈Z|H(X)=0},
infX =inf{∈Z|H(X)=0}, and ampX =supX−infX.
By convention, supX= −∞and infX= ∞if H(X)=0.
Thesupportof a complexXis the set
SuppRX= {ᒍ∈SpecR|Xᒍ 0} =
SuppRH(X).
As usual MinRXis the subset of minimal elements in the support.
Thedepthand the (Krull) dimensionof an R-complex X are defined as follows:
depthRX= −sup(RHomR(k, X)), for X∈D−(R), and dimRX=sup{dimR/ᒍ−infXᒍ|ᒍ∈SuppRX},
cf. [6, Sec. 3]. For modules these notions agree with the usual ones. It follows from the definition that
(1.1) dimRX≥dimRᒍXᒍ+dimR/ᒍ
forX ∈D(R)andᒍ∈SpecR; and there are always inequalities:
−infX≤dimRX for X∈D+(R); and (1.2)
−supX≤depthRX for X∈D−(R).
(1.3)
A complex X ∈ Dbf(R) is Cohen-Macaulay if and only if dimRX = depthRX, that is, if an only if theCohen-Macaulay defect,
cmdRX=dimRX−depthRX,
is zero. For complexes inDbf(R)the Cohen-Macaulay defect is always non- negative, cf. [6, Cor. 3.9].
2. Anchor Prime Ideals
In [4] we introduced associated prime ideals for complexes. The analysis of the support of a complex is continued in this section, and the aim is now to identify the prime ideals that do for complexes what the minimal ones do for modules.
Definitions2.1. LetX ∈ D+(R); we say thatᒍ ∈ SpecR is ananchor prime ideal forX if and only if dimRᒍXᒍ = −infXᒍ > −∞. The set of anchor prime ideals forXis denoted by AncRX; that is,
AncRX= {ᒍ∈SuppRX|dimRᒍXᒍ+infXᒍ=0}.
Forn∈N0we set
Wn(X)= {ᒍ∈SuppRX|dimRX−dimR/ᒍ+infXᒍ≤n}.
Observation 2.2. Let S be a multiplicative system in R, and let ᒍ ∈ SpecR. If ᒍ∩S = ∅ then S−1ᒍ is a prime ideal in S−1R, and for X ∈ D(R) there is an isomorphism S−1XS−1ᒍ Xᒍ in D(Rᒍ). In particular, infS−1XS−1ᒍ=infXᒍand dimS−1RS−1ᒍS−1XS−1ᒍ=dimRᒍXᒍ. Thus, the next biconditional holds forX ∈D+(R)andᒍ∈SpecRwithᒍ∩S= ∅.
(2.1) ᒍ∈AncRX ⇐⇒ S−1ᒍ∈AncS−1RS−1X.
Theorem2.3. ForX∈D+(R)there are inclusions:
MinRX⊆AncRX; and (a)
W0(X)⊆AncRX.
(b)
Furthermore, if ampX = 0, that is, if X is equivalent to a module up to a shift, then
(c) AncRX=MinRX⊆AssRX;
and ifX is Cohen-Macaulay, that is,X ∈ Dbf(R)and dimRX = depthRX, then
(d) AssRX⊆AncRX=W0(X).
Proof. In the followingXbelongs toD+(R).
(a): If ᒍ belongs to MinRX then SuppRᒍXᒍ = {ᒍᒍ}, so dimRᒍXᒍ =
−infXᒍ, that is,ᒍᒍ∈AncRᒍXᒍand henceᒍ∈AncRXby (2.1).
(b): Assume thatᒍbelongs to W0(X), then dimRX = dimR/ᒍ−infXᒍ, and since dimRX≥dimRᒍXᒍ+dimR/ᒍand dimRᒍXᒍ≥ −infXᒍ, cf. (1.1) and (1.2), it follows that dimRᒍXᒍ= −infXᒍ, as desired.
(c): ForM ∈D0(R)we have
AncRM = {ᒍ∈SuppRM |dimRᒍMᒍ=0} =MinRM,
and the inclusion MinRM ⊆AssRMis well-known.
(d): Assume thatX ∈ Dbf(R)and dimRX = depthRX, then dimRᒍXᒍ = depthRᒍXᒍfor allᒍ∈SuppRX, cf. [5, (16.17)]. Ifᒍ∈AssRXwe have
dimRᒍXᒍ=depthRᒍXᒍ= −supXᒍ≤ −infXᒍ,
cf. [4, Def. 2.3], and it follows by (1.2) that equality must hold, soᒍbelongs to AncRX.
For eachᒍ∈SuppRXthere is an equality
dimRX=dimRᒍXᒍ+dimR/ᒍ,
cf. [5, (17.4)(b)], so dimRX−dimR/ᒍ+infXᒍ=0 forᒍwith dimRᒍXᒍ=
−infXᒍ. This proves the inclusion AncRX⊆W0(X). Corollary2.4.ForX ∈Db(R)there is an inclusion:
(a) MinRX⊆AssRX∩AncRX;
and forᒍ∈AssRX∩AncRXthere is an equality:
(b) cmdRᒍXᒍ=ampXᒍ.
Proof. Part (a) follows by 2.3 (a) and [4, Prop. 2.6]; part (b) is immediate by the definitions of associated and anchor prime ideals, cf. [4, Def. 2.3].
Corollary2.5.IfX∈D+f(R), then
dimRX =sup{dimR/ᒍ+dimRᒍXᒍ|ᒍ∈AncRX}.
Proof. It is immediate by the definitions that
dimRX=sup{dimR/ᒍ−infXᒍ|ᒍ∈SuppRX}
≥sup{dimR/ᒍ−infXᒍ|ᒍ∈AncRX}
=sup{dimR/ᒍ+dimRᒍXᒍ|ᒍ∈AncRX};
and the opposite inequality follows by 2.3 (b).
Proposition2.6. The following hold:
(a) If X∈D+(R)andᒍbelongs toAncRX, thendimRᒍ(HinfXᒍ(Xᒍ))=0.
(b) If X∈Dbf(R), thenAncRXis a finite set.
Proof. (a): Assume thatᒍ∈AncRX; by [6, Prop. 3.5] we have
−infXᒍ=dimRᒍXᒍ≥dimRᒍ(HinfXᒍ(Xᒍ))−infXᒍ,
and hence dimRᒍ(HinfXᒍ(Xᒍ))=0.
(b): By (a) every anchor prime ideal forXis minimal for one of the homo- logy modules ofX, and whenX ∈Dbf(R)each of the finitely many homology modules has a finite number of minimal prime ideals.
Observation2.7. By Nakayama’s lemma it follows that inf K(x1, . . . , xn;Y )=infY, forY ∈D+f(R)and elementsx1, . . . , xn∈ᒊ.
Proposition2.8 (Dimension of Koszul Complexes). The following hold for a complexY ∈D+f(R)and elementsx1, . . . , xn∈ᒊ:
dimRK(x1, . . . , xn;Y ) (a)
=sup{dimR/ᒍ−infYᒍ|ᒍ∈SuppRY ∩V(x1, . . . , xn)}; and dimRY −n≤dimRK(x1, . . . , xn;Y )≤dimRY.
(b)
Furthermore:
The elementsx1, . . . , xnare contained in a prime ideal (c)
ᒍ∈Wn(Y ); and
dimRK(x1, . . . , xn;Y )=dimRY if and only ifx1, . . . , xn ∈ᒍ (d)
for someᒍ∈W0(Y ).
Proof. Since SuppRK(x1, . . . , xn;Y ) = SuppRY ∩V(x1, . . . , xn) (see [6, p. 157] and [4, 3.2]) (a) follows by the definition of Krull dimension and 2.7. In (b) the second inequality follows from (a); the first one is established through four steps:
1◦ Y = R: The second equality below follows from the definition of Krull dimension as SuppRK(x1, . . . , xn) = SuppRH0(K(x1, . . . , xn)) = V(x1, . . . , xn), cf. [4, 3.2]; the inequality is a consequence of Krull’s Prin- cipal Ideal Theorem, see for example [8, Thm. 13.6].
dimRK(x1, . . . , xn;Y )=dimRK(x1, . . . , xn)
=sup{dimR/ᒍ|ᒍ∈V(x1, . . . , xn)}
=dimR/(x1, . . . , xn)
≥dimR−n
=dimRY −n.
2◦Y =B, a cyclic module: Byx¯1, . . . ,x¯nwe denote the residue classes in Bof the elementsx1, . . . , xn; the inequality below is by 1◦.
dimRK(x1, . . . , xn;Y )=dimRK(x¯1, . . . ,x¯n)
=dimBK(x¯1, . . . ,x¯n)
≥dimB−n
=dimRY−n.
3◦ Y = H ∈ D0f(R): We setB = R/AnnRH; the first equality below follows by [6, Prop. 3.11] and the inequality by 2◦.
dimRK(x1, . . . , xn;Y )=dimRK(x1, . . . , xn;B)
≥dimRB−n
=dimRY−n.
4◦Y ∈Dbf(R): The first equality below follows by [6, Prop. 3.12] and the last by [6, Prop. 3.5]; the inequality is by 3◦.
dimRK(x1, . . . , xn;Y )=sup{dimRK(x1, . . . , xn;H(Y ))−|∈Z}
≥sup{dimRH(Y )−n−|∈Z}
=dimRY −n.
This proves (b).
In view of (a) it now follows that
dimRY−n≤dimR/ᒍ−infYᒍ
for someᒍ ∈ SuppRY ∩V(x1, . . . , xn). That is, the elementsx1, . . . , xn are contained in a prime idealᒍ∈SuppRY with
dimRY −dimR/ᒍ+infYᒍ≤n, and this proves (c).
Finally, it is immediate by the definitions that
dimRY =sup{dimR/ᒍ−infYᒍ|ᒍ∈SuppRY∩V(x1, . . . , xn)} if and only if W0(Y )∩V(x1, . . . , xn)= ∅. This proves (d).
Theorem2.9. IfY ∈Dbf(R), then the next two numbers are equal.
d(Y )=dimRY +infY; and
s(Y )=inf{s ∈N0| ∃x1, . . . , xs :ᒊ∈AncRK(x1, . . . , xs;Y )}.
Proof. There are two inequalities to prove.
d(Y )≤s(Y ): Letx1, . . . , xs ∈ᒊbe such thatᒊ∈AncRK(x1, . . . , xs;Y ); by 2.8 (b) and 2.7 we then have
dimRY−s ≤dimRK(x1, . . . , xs;Y )= −inf K(x1, . . . , xs;Y )= −infY, so d(Y )≤s, and the desired inequality follows.
s(Y ) ≤ d(Y ): We proceed by induction on d(Y). If d(Y ) = 0 thenᒊ ∈ AncRY so s(Y ) = 0. If d(Y ) > 0 thenᒊ ∈AncRY, and since AncRY is a finite set, by 2.6(b), we can choose an elementx ∈ᒊ− ∪ᒍ∈AncRYᒍ. We set K = K(x;Y ); it is cleat that s(Y ) ≤ s(K)+1. Furthermore, it follows by 2.8 (a) and 2.3 (b) that dimRK <dimRY and thereby d(K) <d(Y ), cf. 2.7.
Thus, by the induction hypothesis we have
s(Y )≤s(K)+1≤d(K)+1≤d(Y );
as desired.
3. Parameters
By 2.9 the next definitions extend the classical notions of systems and se- quences of parameters for finite modules (e.g., see [8, § 14] and the appendix in [2]).
Definitions3.1. LetY belong toDbf(R)and setd = dimRY +infY. A set of elementsx1, . . . , xd ∈ᒊare said to be asystem of parametersforY if and only ifᒊ∈AncRK(x1, . . . , xd;Y ).
A sequence x = x1, . . . , xn is said to be aY-parameter sequenceif and only if it is part of a system of parameters forY.
Lemma3.2. LetYbelong toDbf(R)and setd =dimRY+infY. The next two conditions are equivalent for elementsx1, . . . , xd ∈ᒊ.
(i) x1, . . . , xdis a system of parameters forY. (ii) For everyj ∈ {0, . . . , d}there is an equality:
dimRK(x1, . . . , xj;Y )=dimRY −j;
andxj+1, . . . , xdis a system of parameters forK(x1, . . . , xj;Y ).
Proof. (i)⇒(ii): Assume thatx1, . . . , xdis a system of parameters forY, then
−inf K(x1, . . . , xd;Y )=dimRK(x1, . . . , xd;Y )
=dimRK(xj+1, . . . , xd;K(x1, . . . , xj;Y )
≥dimRK(x1, . . . , xj;Y )−(d−j) by 2.8 (b)
≥dimRY −j−(d−j) by 2.8 (b)
=dimRY −d
= −infY.
By 2.7 it now follows that−infY =dimRK(x1, . . . , xj;Y )−(d−j), so dimRK(x1, . . . , xj;Y )=d−j−infY =dimRY −j, as desired. It also follows that d(K(x1, . . . , xj;Y ))=d−j, and since
ᒊ∈AncRK(x1, . . . , xd;Y )=AncRK(xj+1, . . . , xd;K(x1, . . . , xj;Y )), we conclude thatxj+1, . . . , xdis a system of parameters for K(x1, . . . , xj;Y ).
(ii)⇒(i): If dimRK(x1, . . . , xj;Y )=dimRY−jthen d(K(x1, . . . , xj;Y ))
= d−j; and ifxj+1, . . . , xdis a system of parameters for K(x1, . . . , xj;Y ) thenᒊbelongs to
AncRK(xj+1, . . . , xd;K(x1, . . . , xj;Y ))=AncRK(x1, . . . , xd;Y ), sox1, . . . , xdmust be a system of parameters forY.
Proposition3.3. LetY ∈Dbf(R). The following conditions are equivalent for a sequencex=x1, . . . , xninᒊ.
(i) xis aY-parameter sequence.
(ii) For eachj ∈ {0, . . . , n}there is an equality:
dimRK(x1, . . . , xj;Y )=dimRY −j;
andxj+1, . . . , xnis aK(x1, . . . , xj;Y )-parameter sequence.
(iii) There is an equality:
dimRK(x1, . . . , xn;Y )=dimRY −n.
Proof. It follows by 3.2 that (i) implies (ii), and (iii) follows from (ii). Now, setK = K(x;Y )and assume that dimRK = dimRY −n. Choose, by 2.9,
s =s(K)= dimRK+infKelementsw1, . . . , ws inᒊsuch thatᒊbelongs to AncRK(w1, . . . , ws;K) = AncRK(x1, . . . , xn, w1, . . . , ws;Y ). Then, by 2.7, we have
n+s =(dimRY −dimRK)+(dimRK+infK)=dimRY +infY =d, sox1, . . . , xn, w1, . . . , ws is a system of parameters forY, whencex1, . . . , xn
is aY-parameter sequence.
We now recover a classical result (e.g., see [2, Prop. A.4]):
Corollary 3.4. Let M be an R-module. The following conditions are equivalent for a sequencex=x1, . . . , xninᒊ.
(i) xis anM-parameter sequence.
(ii) For eachj ∈ {0, . . . , n}there is an equality:
dimRM/(x1, . . . , xj)M =dimRM −j;
andxj+1, . . . , xnis anM/(x1, . . . , xj)M-parameter sequence.
(iii) There is an equality:
dimRM/(x1, . . . , xn)M =dimRM−n.
Proof. By [6, Prop. 3.12] and [5, (16.22)] we have dimRK(x1, . . . , xj;M)
=sup{dimR(M⊗LRH(K(x1, . . . , xj)))−|∈Z}
=sup{dimR(M⊗RH(K(x1, . . . , xj)))−|∈Z}
=dimR(M⊗RR/(x1, . . . , xj)).
Theorem3.5. Let Y ∈ Dbf(R). The following hold for a sequencex = x1, . . . , xninᒊ.
(a) There is an inequality:
amp K(x;Y )≥ampY; and equality holds if and only ifxis aY-sequence.
(b) There is an inequality:
cmdRK(x;Y )≥cmdRY;
and equality holds if and only ifxis aY-parameter sequence.
(c) Ifxis a maximalY-sequence, then
ampY ≤cmdRK(x;Y ).
(d) Ifxis a system of parameters forY, then cmdRY ≤amp K(x;Y ).
Proof. In the followingKdenotes the Koszul complex K(x;Y ). (a): Immediate by 2.7 and [4, Prop. 5.1].
(b): By [4, Thm. 4.7 (a)] and 2.8 (b) we have
cmdRK=dimRK−depthRK=dimRK+n−depthRY ≥cmdRY, and by 3.3 equality holds if and only ifxis aY-parameter sequence.
(c): Supposexis a maximalY-sequence, then ampY =supY−infK by 2.7
= −depthRK−infK by [4, Thm. 5.4]
≤cmdRK by (1.2).
(d): Supposexis system of parameters forY, then ampK=supK+dimRK
≥dimRK−depthRK by (1.3)
=cmdRY by (b).
Theorem3.6. The following hold forY ∈Dbf(R). (a) The next four conditions are equivalent.
(i) There is a maximal Y-sequence which is also a Y-parameter se- quence.
(ii) depthRY +supY ≤dimRY+infY. (ii’) ampY ≤cmdRY.
(iii) There is a maximal strongY-sequence which is also aY-parameter sequence.
(b) The next four conditions are equivalent.
(i) There is a system of parameters forY which is also aY-sequence.
(ii) dimRY +infY ≤depthRY+supY. (ii’) cmdRY ≤ampY.
(iii) There is a system of parameters for Y which is also a strong Y- sequence.
(c) The next four conditions are equivalent.
(i) There is a system of parameters forY which is also a maximal Y- sequence.
(ii) dimRY +infY =depthRY +supY. (ii’) cmdRY =ampY.
(iii) There is a system of parameters forYwhich is also a maximal strong Y-sequence.
Proof. Let Y ∈ Dbf(R), set n(Y ) = depthRY + supY and d(Y ) = dimRY +infY.
(a): A maximal Y-sequence is of length n(Y ), cf. [4, Cor. 5.5], and the length of aY-parameter sequence is at most d(Y ). Thus, (i) implies (ii) which in turn is equivalent to (ii’). Furthermore, a maximal strongY-sequence is, in particular, a maximalY-sequence, cf. [4, Cor. 5.7], so (iii) is stronger than (i). It is now sufficient to prove the implication (ii)⇒(iii): We proceed by induction.
If n(Y ) = 0 then the empty sequence is a maximal strongY-sequence and a Y-parameter sequence. Let n(Y ) > 0; the two sets AssRY and W0(Y ) are both finite, and since 0 < n(Y ) ≤ d(Y ) none of them containᒊ. We can, therefore, choose an elementx ∈ᒊ− ∪AssRY∪W0(Y )ᒍ, andxis then a strong Y-sequence, cf. [4, Def. 3.3], and aY-parameter sequence, cf. 3.3 and 2.8. Set K = K(x;Y ), by [4, Thm. 4.7 and Prop. 5.1], respectively, 2.8 and 2.7 we have
depthRK+supK=n(Y )−1≤d(Y )−1=dimRK+infK.
By the induction hypothesis there exists a maximal strongK-sequencew1, . . . , wn−1which is also aK-parameter sequence, and it follows by [4, 3.5] and 3.3 thatx, w1, . . . , wn−1is a strongY-sequence and aY-parameter sequence, as wanted.
The proof of (b) i similar to the proof of (a), and (c) follows immediately by (a) and (b).
Theorem3.7. The following hold forY ∈Dbf(R):
(a) If ampY =0, then anyY-sequence is aY-parameter sequence.
(b) If cmdRY =0, then anyY-parameter sequence is a strongY-sequence.
Proof. The empty sequence is aY-parameter sequence as well as a strong Y-sequence, this founds the base for a proof by induction on the lengthnof
the sequencex=x1, . . . , xn. Letn >0 and setK=K(x1, . . . , xn−1;Y ); by 2.8 (a) we have
(∗)
dimRK(x1, . . . , xn;Y )=dimRK(xn;K)
=sup{dimR/ᒍ−infKᒍ|ᒍ∈SuppRK∩V(xn)}.
Assume that ampY = 0. Ifxis aY-sequence, then ampK =0 by 3.5 (a) andxn ∈zRK, cf. [4, Def. 3.3]. As zRK= ∪ᒍ∈AssRKᒍ, cf. [4, 2.5], it follows by (b) and (c) in 2.3 thatxnis not contained in any prime idealᒍ∈W0(K); so from(∗)we conclude that dimRK(xn;K) <dimRK, and it follows by 2.8 (b) that dimRK(xn, K) = dimRK−1. By the induction hypothesis dimRK = dimRY−(n−1), so dimRK(x1, . . . , xn;Y )=dimRY −nand it follows by 3.3 thatxis aY-parameter sequence. This proves (a).
We now assume that cmdRY =0. Ifxis aY-parameter sequence then, by the induction hypothesis,x1, . . . , xn−1is a strongY-sequence, so it is sufficient to prove thatxn∈ZRK, cf. [4, 3.5]. By 3.3 it follows thatxnis aK-parameter sequence, so dimRK(xn;K) = dimRK−1 and we conclude from(∗)that xn ∈ ∪ᒍ∈W0(K)ᒍ. Now, by 3.5 (b) we have cmdRK = 0, so it follows from 2.3 (d) thatxn ∈ ∪ᒍ∈AssRKᒍ=ZRK. This proves (b).
Semi-dualizing Complexes3.8. We recall two basic definitions from [3]:
A complexC ∈Dbf(R)is said to besemi-dualizingforRif and only if the homothety morphismχCR:R →RHomR(C, C)is an isomorphism [3, (2.1)].
LetC be a semi-dualizing complex forR. A complexY ∈ Dbf(R)is said to beC-reflexiveif and only if thedagger dualY†C =RHomR(Y, C)belongs toDbf(R)and the biduality morphismδCY:Y →RHomR(RHomR(Y, C), C) is invertible inD(R)[3, (2.7)].
Relations between dimension and depth forC-reflexive complexes are stud- ied in [3, sec. 3], and the next result is an immediate consequence of [3, (3.1) and (2.10)].
Let C be a semi-dualizing complex for R and let Z be aC-reflexive complex. The following holds for ᒍ ∈ SpecR: If ᒍ ∈ AncRZ then ᒍ∈AssRZ†C, and the converse holds inCis Cohen-Macaulay.
Adualizing complex, cf. [7], is a semi-dualizing complex of finite injective dimension, in particular, it is Cohen-Macaulay, cf. [3, (3.5)]. IfDis a dualizing complex forR, then, by [7, Prop. V.2.1], all complexesY ∈ Dbf(R)areD- reflexive; in particular, all finiteR-modules areD-reflexive and, therefore, [4, 5.10] is a special case of the following:
Theorem3.9. LetCbe a Cohen-Macaulay semi-dualizing complex forR, and letx = x1, . . . , xn be a sequence inᒊ. IfY isC-reflexive, thenx is a Y-parameter sequence if and only if it is aRHomR(Y, C)-sequence; that is
xis aY-parameter sequence ⇐⇒ xis aRHomR(Y, C)-sequence.
Proof. We assume thatC is a Cohen-Macaulay semi-dualizing complex forRand thatY isC-reflexive, cf. 3.8. The desired biconditional follows by the next chain, and each step is explained below (we use the notation −†C introduced in 3.8).
xis aY-parameter sequence ⇐⇒ cmdRK(x;Y )=cmdRY
⇐⇒ amp K(x;Y )†C =ampY†C
⇐⇒ amp K(x;Y†C)=ampY†C
⇐⇒ xis aY†C-sequence.
The first biconditional follows by 3.5 (b) and the last by 3.5 (a). Since K(x)is a bounded complex of free modules (hence of finite projective dimension), it follows from [3, Thm. (3.17)] that also K(x;Y )isC-reflexive, and the second biconditional is then immediate by the CMD-formula [3, Cor. (3.8)]. The third one is established as follows:
K(x;Y )†C RHomR(K(x)⊗LRY, C) RHomR(K(x), Y†C) RHomR(K(x), R⊗LRY†C) RHomR(K(x), R)⊗LRY†C
∼K(x)⊗LRY†C K(x;Y†C),
where the second isomorphism is by adjointness and the fourth by, so- called, tensor-evaluation, cf. [1, (1.4.2)]. It is straightforward to check that HomR(K(x), R)is isomorphic to the Koszul complex K(x)shiftedndegrees to the right, and the symbol∼denotes isomorphism up to shift.
IfCis a semi-dualizing complex forR, then bothCandRareC-reflexive complexes, cf. [3, (2.8)], so we have an immediate corollary to the theorem:
Corollary3.10. IfC is a Cohen-Macaulay semi-dualizing complex for R, then the following hold for a sequencex=x1, . . . , xninᒊ.
(a) xis aC-parameter sequence if and only if it is anR-sequence.
(b) xis anR-parameter sequence if and only if it is aC-sequence.
Acknowledgements.The author would like to thank professor Srikanth Iyengar and professor Hans-Bjørn Foxby for taking the time to discuss the material presented here.
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