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CHARACTERIZATIONS OF TRIPOTENTS IN JB*-TRIPLES

REMO V. HÜGLI

Abstract

The setU(A)of tripotents in a JB-tripleAis characterized in various ways. Some of the char- acterizations use only the norm-structure ofA. The partial order onU(A)as well asσ-finiteness of tripotents are described intrinsically in terms of the facial structure of the unit ballA1inA, i.e.

without reference to the (pre-)dual ofA. This extends similar results obtained in [6] and simplifies the metric characterization of partial isometries inC-algebras found in [1] (cf. [8]).

1. Introduction

In this article several conditions upon an elementain a JB-tripleA, necessary and sufficient for a to be a tripotent, i.e. that{a a a} = a are established.

The results are based on the intricate connections that persist between the algebraic orthogonality onAand the M-orthogonality, the former being defined in JB-triples, the later in any normed vectorspace. Thereby we obtain a purely geometric description of the algebraic concept of tripotents. To be explicit, the M-complementaof the elementainAis defined to be the set of all elements bin Asuch thata±b = max{a,b}. We show that an element a of norm one in a JB-tripleAis a tripotent if and only if

aA1=iaA1,

whereA1denotes the closed unit-ball ofAandithe imaginary unit. This as well as further characterizations of tripotents are provided in Theorem 4.1.

The setU(A)of tripotents inAis endowed with a partial order≤which is defined algebraically. It is shown that(U(A),≤)is anti-order isomorphic to the partial order(FU(A),⊆)of faces inA1generated by tripotents inA, ordered by set inclusion. The mappingu → face(u)is the corresponding anti-order isomorphism. This is shown in Theorem 4.4 which is a variation of results by Edwards and Rüttimann in [6] and [7], concerning the case of JBW-triples and their pre-duals. Similar investigations were persued by Friedman and Russo,

Supported in part by the Swiss National Science Foundation.

Received December 6, 2004; in revised form November 7, 2005.

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whose concept of facially symmetric spaces represents a geometric description of the pre-duals of JBW-triples [11], [12]. Our description of(U(A),≤)is completely intrinsic toA1, i.e. it does not use any reference to the (pre-) dual of A, and it is valid for general JB-triples. In Theorem 4.5 the results are applied to obtain also an intrinsic characterization ofσ-finite tripotents.

The category of JB-triples is strictly more general than those of some well known operator algebras, includingC-algebras and JB-algebras. The tripotents of aC-algebra are precisely its partial isometries. A metric char- acterization of the partial isometries in aC-algebra was provided earlier by Akeman and Weaver in [1]. Theorem 5.3 shows that their result can be seen as a special case of ours. For another proof of this result in complex as well as real JB-triples we refer to the work by Fernandez-Polo, Martíinez Moreno and Peralta [8]. However, the explicit description by M-orthogonality has not been observed earlier.

The techniques used in this article are based on numerous works on JB- triples and JBW-triples, in particular on [4], [6], [9], [11], [12], [13], [14], [16] and [17].

2. Preliminaries

LetC be a convex subset in a vectorspaceE. A convex subsetF ofCis said to be a faceofC if the following implications hold: If for somet(0,1) anda, bC, the convex combination ta+(1−t)blies in F thena andb themselves lie inF. Since the intersection of a family of faces ofC is also a face ofC, for each subsetHofC, there exists the smallest face ofCcontaining H, denoted faceC(H )and referred to as the face ofCgeneratedbyH. Hence, the setF(C)of all faces ofC, ordered by set inclusion, is a complete lattice with least element the empty set∅and largest element C. Letτ be a locally convex Hausdorff topology onEand letCbeτ-closed. A faceF ofCis said to beτ-exposedif there exists aτ-continuous linear functionalf onEand a real numbert such that, for all elementsainC,

Re(f (a))

=t ifaF

< t else .

An arbitrary intersection ofτ-exposed faces is said to be aτ-semi-exposed face ofC. LetFτ(C), Eτ(C)andSτ(C)denote the sets ofτ-closed, τ-exposed andτ-semi-exposed faces ofC respectively. When ordered by set inclusion, Fτ(C)andSτ(C)are complete lattices.

WhenEis a normed vectorspace with dual spaceEthe abbreviationsn andw will be used for the norm topology ofEand the weak topology of E. For an elementaofE1, define face(a)to be the smallest face ofE1which

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containsa. LetH andGbe subsets of the unit ballE1inEand of the unit ball E1ofErespectively. The setsHandGare defined by

(2.1) H= {f ∈E1:f (a)=1∀a∈H};

G= {a∈E1:a(f )=1∀f ∈G}.

Observe that(H) is the least element ofSn(E1)containingH, and (G) is the least element ofSw(E1)containingG. For more details, the reader is referred to [6], [7].

Two elements a and b of a normed vectorspace E are said to be M- orthogonal, denotedab, if

(2.2)b =max{a,b}.

For a subsetH of the normed vectorspaceE, theM-orthogonal complement (briefly the M-complement)HofH is defined by

(2.3) H= {a∈E:ab,∀b∈H}.

For a singleton set{a}we writeainstead of{a}. Similarly, we writeaand fifaEandfE.

The M-complement is related to the facial structure of the unit-ballE1of E, as can be seen from straightforward considerations such as the following.

Proposition2.1. Letabe an element in the closed unit ballE1of a normed vectorspaceE. Then,

a+(aE1)⊆face(a).

Proof. Consider an elementbina+(aE1), that isb=a+cfor some c(aE1). Thena±c ≤1. Hence botha+candaclie inE1. Since acan be written as the convex combination

a = 1

2(a+c)+ 1

2(ac),

it follows thatb(and alsoac) lies in face(a), as required.

The definitions of M-orthogonality and the M-complement make sense in real and complex normed vectorspaces. However, in the sequel we will assume Eto be complex. Denote byS1(C)andS1(E)the unit sphere in the complex planeCand inEand byC1the closed unit disc ofC. Thetangent discSaand

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theflat tangent spaceRacorresponding to an elementaofS1(E)are defined by

Sa= {b∈E:a+sb =1∀s∈C1}, (2.4)

Ra=linCSan

. (2.5)

The relations presented in the following lemma will be useful in subsequent considerations. They were proved in [4] Lemma 2.11.

Lemma2.2. Letabe an element of norm one in a complex normed vector- spaceE. Then:

(i) aE1= {b∈E:a+tb =1,∀t ∈[−1,1]}, (ii) iaaE1⊆√

2· {b∈E:a+zb =1∀z∈C1}, (iii) i(aE1)=(ia)E1,

(iv) linR(iaaE1)=linC(iaaE1),

By (iii) the brackets in those expressions can be omitted. From (i) it is easially seen thatSaiaaE1. It follows from (ii) and (iv) that,

SaiaaE1⊆√ 2Sa, (2.6)

Ra=linCiaaE1 n. (2.7)

The case in whichEis a JB-triple is the subject of the remaining sections.

3. JB-triples and JBW-triples

A Jordan-triple is complex vectorspace A equipped with a triple product (a, b, c) → {a b c}fromA×A×AtoAwhich is symmetric and linear in the first and third variable, conjugate linear in the second variable and satisfies theJordan triple identity

[D(a, b), D(c, d)]=D({a b c}, d)D(c,{d a b}),

where [, ] denotes the commutator, andD(a, b)is the linear mapping onA defined byD(a, b)c= {a b c}. A subspaceBof aAis said to be asubtriple if{B B B}is contained inB.

A JB-tripleis a complex Banach space, which is a Jordan-triple, and the triple product has the following properties. The mapping(a, a)D(a, a)is continuous fromA×Ato the Banach spaceB(A)of bounded linear operators onA, for each elementainA,D(a, a)is hermitian in the sense of [2] Defin- ition 5.1, with non-negative spectrum and has normD(a, a) = a2. IfA

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is also the dual of some Banach spaceA, thenAis said to be a JBW-triple, andAis referred to as thepredualofA.

An important class of examples of JB-triples is given by C-algebras. [13].

WhenAis a C-algebra, the triple product is defined fora, b, cA, by (3.1) {a b c} = 1

2(abc+cba).

A JB-triple behaves locally like a commutative C-algebra, and an analo- gon of the C-condition is valid, as can be seen from the next result. For proofs see [10] and [16].

Lemma3.1. LetAbe aJB-triple and leta,bandcbe elements ofA. Then, the following results hold.

(i) {a b c} ≤ a b c. (ii) {a a a} = a3.

(iii) The closed subtriple generated by an elementa of Ais isometrically isomorphic as a Jordan-triple to a commutativeC-algebra.

A paira, b of elements ofAis said to be orthogonal, denoted abif D(a, b)is identically zero onA. It can be shown that this relation is symmetric.

Thealgebraic annihilatorHof a non-empty subsetH ofAis defined to be the set

H= {a∈A:ab∀bH} =

b∈H

b.

Observe that H is a norm closed subtriple ofA, andH is weak-closed whenAis a JBW-triple. As it was observed in [9] the properties described in Lemma 3.1 imply that the algebraic annihilator and the M-orthocomplement ofH are related by

(3.2) HH.

For anyaA, definea3 = {a a a}. Higher powers ofa can be defined unambiguously using the Jordan triple identity, by

a2n+1= {a a a2n−1} = {a a2n−1a}.

An elementuinAis said to be atripotent ifu3 =u. The set of all tripotents ofAis denoted byU(A). Ifuandvare tripotents ofAsuch that

u(vu),

then, uis said to be less than or equal to v, denoted uv. This relation provides a partial order onU(A)[17]. A tripotent uin Aisσ-finite, if any

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set of pairwise orthogonal tripotents all of which are less than or equal touis of countable cardinality. The set of allσ-finite tripotents ofAis denoted by Uσ(A).

The partial order(U(A),≤)has no largest element, except whenAis the null-vectorspace. Hence we may adjoin toU(A)an abstract largest element which we denote byω, and we defineU(A)to be the setU(A)∪ {ω}. The investigations of the facial structure ofA1carried out in [6] show that whenA is a JBW-triple with predualA, then the setsFn(A1)andEn(A1)coincide, and alsoFw(A1)andEw(A1)coincide. Let the setsωand)be defined by

(3.3) ω=A1, )= ∅.

This extends the mappingsGGandG(G)to subsets ofU(A). The next Lemma, which was obtained in [6], presents some profound connections betweenFn(A1),Fw(A1)andU(A).

Lemma3.2. LetAbe aJBW-triple with predualA. Then, the following results hold.

(i) The mappinguuis an order isomorphism from the partially ordered setU(A)of tripotents inA, with a largest element adjoined, onto the complete latticeFn(A∗,1)of all norm-closed faces of the closed unit ball A∗,1inA, and, hence,U(A)is a complete lattice.

(ii) The mappingu(u)is an anti-order-isomorphism fromU(A)onto the complete lattice Fw(A1)of weak-closed faces of the closed unit ballA1inAand

(u)=u+(uA1).

The final result of this section connects the M-complement and the annihil- ator of subsets ofU(A). A proof can be found in [4] Corollary 4.3.

Lemma3.3. LetAbe aJB-triple and letH be a non-empty subset of the setU(A)of tripotents inA. Then, the setsHA1andHA1coincide.

4. Characterizations of tripotents

With the information presented so far, it is possible to establish the main results.

Theorem4.1. LetAbe aJB-triple and letabe an element inAof norm one. Then, the following conditions are equivalent.

(1) aU(A),

(2) aA1=aA1,

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(3) aA1aA1, (4) aA1=iaA1, (5) Sa=aA1, (6) Ra =a.

Proof. Ifais a tripotent ofA, then (2) and (3) are immediate from Lemma 3.3. Notice thatais a complex subspace ofA, thata=(ia), and that, by Lemma 2.2(iii), the setsi(aA1)and(ia)A1coincide. It follows from (2) that

iaA1=aA1=aA1.

This proves (4). To show (5), combine (2) with the relations (2.6) to obtain SaaiaA1=aA1.

For the reverse inclusion, let b be any element of aA1. Since a is a complex subspace ofA, it follows from (2) that, for allsS1(C),

sbaA1=aA1. Therefore,

a+sb =max{a,sb} =1,

that is,blies inSa. This proves (5). The condition (6) is immediate from (5) by taking the closed linear span.

Suppose, thatais not a tripotent. In order to disprove (2), (3) and (4), we need to find an elementbwhich lies inaA1but not inaia. Similarly, we show hat there exists an elementcwhich lies inSabut not ina. By (2.6) and (2.7) this will disprove (5) and (6). The sought after elementsbandccan be obtained from the spectral calculus, described in Lemma 3.1(iii). This is made explicit in the remainder of the proof.

Denote by B the smallest norm-closed subtriple of A containinga. By Lemma 3.1(ii), there exists a triple isomorphismϕfromBonto the commut- ative C-algebraC0(X)of continuous complex-valued functions on a locally compact subsetXof [0,1] which vanish at zero. Observe thatϕ(a)is equal to the functionιdefined, fort inX, by

ι(t)=t.

A functionf inC0(X)is a tripotent if and only iff (X)S1(C)∪ {0}. The assumption thatais not a tripotent implies that there exists an elementt0inX such that

0< t0<1.

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Letgbe the element ofC0(X)defined, fortXby

g(t)=



i

1−t2

1− |t−t0| 1−t0

, if|t−t0| ≤1−t0

0, if|t−t0|>1−t0

.

Clearly, g has norm not greater than one in C0(X), i.e. g lies in C0(X)1. Moreover, for all elementst inX,

|(ι+g)(t)| ≤1, |(ι−g)(t)| ≤1, and, fort =t0,

|(ι+g)(t0)| = |(ιg)(t0)| =1.

Therefore,ι+gandιghave norm one inC0(X), and, settingb=ϕ1(g) entails

a+b = ab = ϕ1+g) =sup

t∈X|t +g(t)| =1. This shows thataandbare M-orthogonal. On the other hand,

a−ib ≥ |(ιig)(t0)| = |t0ig(t0)| =t0+ 1−t02>1. Hence,a and±ibare not M-orthogonal, andbis not contained inia. Fur- thermore, sinceϕis a triple-isomorphism,

ϕ{b a a}(t0)= {ϕ(b), ϕ(a), ϕ(a)}(t0)= {g ι ι}(t0)= −it02 1−t02=0. Therefore,a and bare not triple-orthogonal. We have shown thatb has the required properties.

Define the functionhinC0(X)by

h(t)=



(1−t)

1− |t−t0| 1−t0

, if|t−t0| ≤1−t0

0, if|t−t0|>1−t0

.

Alsoh lies inC0(X)1, and for all zin C1and all (positive) numberst with

|t −t0| ≤1−t0,

t +z(1−t)

1− |t−t0| 1−t0

≤1.

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The assumption thatahas norm one implies that 1∈X. It follows that, for all zinC1andt inX,

|(ι+zh)(t)| ≤ |t +h(t)| ≤1,

|(ι+zh)(1)| =1.

These relations show thatι+zhhas norm one inC0(X), that is hSι. Set c=ϕ1(h). Thenclies inSa. On the other hand

(ϕ{c a a})(t0)=(1−t0)t02=0. Thereforecis not contained ina. This finishes the proof.

It is well known that two JB-triples are triple isomorphic if and only if they are isometrically isomorphic as Banach spaces. We can use the above theorem to show that surjective linear isometries are algebraic isomorphisms. The con- verse can be proved using some arguments which are not directly connected with the methods considered here, and is therefore omitted. For original proofs the reader is referred to [14] Proposition 2.4 and [16] Proposition 5.5.

Corollary 4.2.Let A andB be JB-triples, and letϕ : AB be a surjective linear isometry betweenAandB. Thenϕis a triple isomorphism.

Proof. Letabe an arbitrary element ofA. Using polarisation of the triple product it can be seen that, fora, b, cA, there exist elements(ak)12k=1inA andk)12k=1inC, such that

(4.1) {a b c} = 12 k=1

αkak3.

As next we show thatϕ(a3)=(ϕ(a))3, for allaA. The bi-adjointϕ∗∗ofϕis a weak-continuous bijective isometry betweenA∗∗andB∗∗. Morevoer, by [3], A∗∗andB∗∗are JBW-triples, containingAandBas subtriples (even ideals) via the canonical embeddings. Therefore,acan be regarded as an element of A∗∗. By [9] there exists an orthogonal family{uj}j∈J of tripotents inA∗∗and complex numbers{αj}j∈K such that

(4.2) a=

j∈J

αjuj, a =sup

j∈Jj|.

The sum in this expression is weak-convergent. Theorem 4.1(2) and Lemma 3.3 imply that{ϕ∗∗(uj)}j∈J is an orthogonal family inU(B∗∗). It follows that

ϕ∗∗(a3)=ϕ∗∗

j∈J

αj3uj

=

j∈J

αj3ϕ∗∗(uj)=∗∗(a))3.

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By Lemma 3.1 and Equation (4.1)ϕis an injective triple homomorphism. This completes the proof.

In the remainder of this section we will be investigating the order structure ofU(A). The following observation seems to have escaped notice so far.

Proposition4.3. Let Abe a JBW-triple and letube a tripotent ofA. Then,

face(u)=(u)=u+(uA1)=u+(uA1).

In particularface(u)is a weak-closed subset ofA1.

Proof. Combine Lemma 3.2, Lemma 3.3 and Proposition 2.1 to obtain face(u)u=u+(uA1)=u+(uA1)⊆face(u).

Hence all of these sets coincide. Clearly(u)is weak-closed. This gives the proof.

Denote byFU(A1)the set of all faces ofA1of the form face(u), for some elementuinU(A). The above proposition and Lemma 3.2(ii) imply that (4.3) Fw(A1)=FU(A1).

As shown in the next theorem, the statement of Proposition 4.3 can be im- proved. It holds in JB-triples and for the norm-semi-exposed face(u) gen- erated byu. This makes it possible to describe the order structure ofU(A)in terms of the facial structure ofA1without referring to the predualA.

Theorem4.4. LetAbe aJB-triple withU(A)the set of its tripotents and FU(A)the set of those faces ofA1which are generated by a tripotent. Then the mapu→face(u)is an anti-order isomorphism between the partial orders (U(A),≤)and(FU(A1),⊆). Moreover,

face(u)=(u)=u+(uA1)=u+(uA1).

In particular, every face ofA1generated by a tripotent is norm-closed.

WhenAis aJBW-triple, then(FU(A)∪ ∅,⊆)is a complete lattice and is anti-order isomorphic to the lattice(U(A),≤).

Proof. WhenAis a JB-triple, letj :AA∗∗denote the canonical em- bedding into its second dualA∗∗, a JBW-triple with predualA[3]. Consider a tripotentuinA. Thenj (u)U(A∗∗). Observe that

(4.4) uu+(uA1)=u+(uA1)⊆faceA1(u)(u).

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Ifbis an element of(u)then by Proposition 4.3,

j (b)(j (u))j (A)=j (u)+(j (u)A∗∗1 )j (A).

Henceblies inu+(uA1)which is therefore a superset of(u). It follows that

(4.5) u+(uA1)=u+(uA1)=faceA1(u)=(u).

The mappingu→faceA1(u)fromU(A)toFU(A)is surjective by definition ofFU(A). To see that it is also injective, letuandvbe a tripotents ofAsuch that faceA1(u)=faceA1(v). Then, by (4.4),

j (u)j (faceA1(v))j ((v))(j (v)).

Hence,(j (u))(j (v)). In a similar way it is shown that(j (v))(j (u)). Hence the equality(j (u)) =(j (v))holds. By Lemma 3.2(ii),uequalsv.

It remains to show thatu→faceA1(u)reverses the order structure. Suppose thatu, vU(A)are such thatuv. Then there exists an elementwinU(A) with the propertieswuandv=u+w. It follows that

vu+(uA1)=u+uA1⊆faceA1(u).

This implies that

faceA1(v)⊆faceA1(u), as required.

In the case whenAis a JBW-triple, it can be seen from Proposition 4.3 and the relations (4.5) that

faceA1(u)=(u)=(u).

By Lemma 3.2,u→faceA1 is an anti-order isomorphims from the complete lattice(U(A),≤)toFU(A). This finishes the proof.

It is now also possible to characterizeσ-finiteness of tripotents in such a way that only the geometry ofA1is used.

Theorem4.5. LetAbe aJB-triple. A tripotentuofAisσ-finite if and only if there are at most countably many elements(ak)k∈K in the unit sphere S1(A)having the properties

(1) for allkK,akA1=iakA1, (2) forj =k,ak aj,

(3) for allkK,face(u)⊆face(ak).

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Proof. By Theorem 4.1, the condition (1) holds if and only if{ak}k∈KU(A). In this case, by Lemma 3.3, the relationaj akis equivalent toajak. The prove is completed using (3) and Theorem 4.4.

5. Applications to C-algebras

As it was shown in [13], any C-algebraAis a JB-triple when equipped with the triple product given by (3.1).

The next lemma presents a well known fact. We include a proof for com- pleteness.

Lemma5.1. LetAbe aC-algebra, equipped with the triple product(3.1).

Then, the set of tripotents ofAcoincides with that of the partial isometries.

Proof. Suppose thatuis a tripotent, i.e.u=uuu, then (uu)2=(uuu)u=uu.

Clearly,uuis also self-adjoint. Henceuis a partial isometry. Conversely, for each partial isometryu, the C-condition implies that

uuuu2= (uuuu)(uuuu)

= uuuuuu−2(uu)2uu =0. Hence,u=uuu, as required.

It is now obvious that we can provide a metric description of the partial isometries inA.

Theorem5.2. A norm one elementaof aC-algberaAis a partial iso- metry if and only ifaA1=iaA1.

Proof. This is an immediate consequence of Theorem 4.1 and Lemma 5.1.

A metric description of partial isometries ofA, different from that in The- orem 5.2 was found in [1]. Comparing those results with ours, we can show that the same description remains valid for tripotents of JB-triples. For a norm-one elementaofA, consider the setsX1(a)andX2(a), defined by

X1(a)= {b∈A:∃r >0 :a+rb = arb =1}, X2(a)= {b∈A; ∀z∈C; a+zb =max{1,zb}}. (5.1) As shown in [1],ais a partial isometry if and only if

X1(a)=X2(a).

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It is worth noting that the conditionsaA1=iaA1andX1(a)=X2(a) are not equivalent in arbitrary complex normed vectorspaces. The question is wether this equivalence holds in JB-triples. The affirmative answer, presented in the next theorem, provides yet another metric characterization of tripotents.

An alternative proof and a generalization to real JB-triples can be found in [8].

Theorem5.3. LetAbe aJB-triple, and letabe an element of norm one inA. Let the setsX1(a)andX2(a)be defined as in(5.1). Thenais a tripotent if and only ifX1andX2coincide.

Proof. Suppose that aU(A). Observe that the inclusion X2X1

is immediate from the definition of these sets. Hence we need only to show that X1X2. Consider an element b in X1, i.e. there exists r > 0 with a±rb =1. Then,

2rb = a+rb(arb) ≤ a+rb + arb =2.

Hencerblies inA1. Since 1=max{a,rb},rblies also ina. From this and Theorem 4.1(3), it follows that

rbaA1=aA1. The relation (3.2) implies that, for allz∈C,

zb= z

rrb ∈C(aA1)=aa. Therefore,blies inX2(a), as required.

Suppose thatX1(a)=X2(a), and consider an elementbinaA1. From Lemma 2.2(i) it can be seen thataA1X1. It follows thatblies inX2(a). In particular

(5.2)ib =max{1,ib} ≤1.

This shows thatiband−ibare elements ofaA1. Henceblies iniaA1. We conclude thataA1iaA1. The reverse inclusion is obtained from similar arguments. By Theorem 4.1(4),ais a tripotent. The proof is complete.

Acknowledgements. Part of the main results presented in this article were obtained in the authors Ph.D. thesis [15]. He wishes to acknowledge the advise of the late G. T. Rüttimann, University of Berne, and of C. M. Edwards, University of Oxford, as well as the support received by H. Carnal, University of Berne.

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DEPT. OF MATHEMATICS UNIVERSITY COLLEGE DUBLIN BELFIELD

DUBLIN 4 IRELAND

E-mail:hugli@maths.ucd.ie

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